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	How to git-lfs without git-lfs? TODO: duplicated gitconfig comments?
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				| @ -79,11 +79,11 @@ | ||||
| 	# I am not developing in detached head state, I generally want to compile | ||||
| 	# a specific version of a program and I know how to get out of it | ||||
| 	detachedHead = false | ||||
| [filter "lfs"] | ||||
| 	clean = git-lfs clean -- %f | ||||
| 	smudge = git-lfs smudge -- %f | ||||
| 	process = git-lfs filter-process | ||||
| 	required = true | ||||
| # [filter "lfs"] | ||||
| # 	clean = git-lfs clean -- %f | ||||
| # 	smudge = git-lfs smudge -- %f | ||||
| # 	process = git-lfs filter-process | ||||
| # 	required = true | ||||
| [status] | ||||
| 	submodulesummary = 1 | ||||
| [submodule] | ||||
|  | ||||
| @ -79,11 +79,11 @@ | ||||
| 	# I am not developing in detached head state, I generally want to compile | ||||
| 	# a specific version of a program and I know how to get out of it | ||||
| 	detachedHead = false | ||||
| [filter "lfs"] | ||||
| 	clean = git-lfs clean -- %f | ||||
| 	smudge = git-lfs smudge -- %f | ||||
| 	process = git-lfs filter-process | ||||
| 	required = true | ||||
| # [filter "lfs"] | ||||
| # 	clean = git-lfs clean -- %f | ||||
| # 	smudge = git-lfs smudge -- %f | ||||
| # 	process = git-lfs filter-process | ||||
| # 	required = true | ||||
| [status] | ||||
| 	submodulesummary = 1 | ||||
| [submodule] | ||||
|  | ||||
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