Implement Jeopardy cashout #18
@ -54,9 +54,20 @@ func (w *WatIntegration) HandleIntegration(m *irc.Message, msgargs []string) boo
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func (w *WatIntegration) Jeopardy(m *irc.Message, msgargs []string) {
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// hey, I avoided regex!
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// 1. Starts parsing an array of message arguments containing "Top finishers: (nick1: 1000) (nick2: 2000)", where
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// the "($nick: $value)" pairs can contain arbitrary nicknames + integer values and can repeat one to any amount of times
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// 2. Join the array on spaces to a string, but skip the first two elements to remove "Top" and "finishers:"
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// 3. Replace ") (" in the string with ";" - the semicolon is chosen as a temporary delimiter because it does not conflict with any other characters in the message
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// 4. Replace ": " in the string with ":"
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// 5. Replace "(" in the string with "" (relevant for the first nick/value pair)
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// 6. Replace ")" in the string with "" (relevant for the last nick/value pair)
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// 7. Now, we have a string like "nick1:1000;nick2:2000" - split it back into an array on ";"
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// 8. The result is an array like "[nick1:1000, nick2:2000]"
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finisherPrizes := strings.Split(strings.Replace(strings.Replace(strings.Replace(strings.Replace(strings.Join(msgargs[2:], " "), ") (", ";", -1), ": ", ":", -1), "(", "", 1), ")", "", 1), ";")
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fmt.Printf("Processing Jeopardy: %s\n", finisherPrizes)
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// iterate over the "$nick:$value" string elements
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for _, pair := range finisherPrizes {
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// turn the string element into an array, where the first entry is the nickname, and the second the value
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nameCoinPair := strings.Split(pair, ":")
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coins, err := strconv.ParseUint(nameCoinPair[1], 10, 64)
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if err != nil {
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