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dpp: factor out key derivation and starting PKEX into functions

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This will make things a bit easier in future patches, and reduces
some of the length/complexity of these functions.
This commit is contained in:
James Prestwood 2024-08-27 07:21:22 -07:00 committed by Denis Kenzior
parent 95a9e052de
commit bf2441e311
1 changed files with 51 additions and 41 deletions
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92
src/dpp.c
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@ -4280,6 +4280,17 @@ static uint32_t *dpp_default_freqs(struct dpp_sm *dpp, size_t *out_len)
return freqs_out;
}
static void __dpp_pkex_start_enrollee(struct dpp_sm *dpp)
{
dpp->current_freq = dpp->freqs[0];
dpp_reset_protocol_timer(dpp, DPP_PKEX_PROTO_TIMEOUT);
l_debug("PKEX start enrollee (id=%s)", dpp->pkex_id ?: "unset");
dpp_start_offchannel(dpp, dpp->current_freq);
}
static bool dpp_pkex_scan_notify(int err, struct l_queue *bss_list,
const struct scan_freq_set *freqs,
void *user_data)
@ -4314,13 +4325,7 @@ static bool dpp_pkex_scan_notify(int err, struct l_queue *bss_list,
dpp->freqs = scan_freq_set_to_fixed_array(freq_set, &dpp->freqs_len);
start:
dpp->current_freq = dpp->freqs[0];
dpp_reset_protocol_timer(dpp, DPP_PKEX_PROTO_TIMEOUT);
l_debug("PKEX start enrollee (id=%s)", dpp->pkex_id ?: "unset");
dpp_start_offchannel(dpp, dpp->current_freq);
__dpp_pkex_start_enrollee(dpp);
return false;
@ -4338,40 +4343,6 @@ static void dpp_pkex_scan_destroy(void *user_data)
static bool dpp_start_pkex_enrollee(struct dpp_sm *dpp)
{
_auto_(l_ecc_point_free) struct l_ecc_point *qi = NULL;
memcpy(dpp->peer_addr, broadcast, 6);
/*
* In theory a driver could support a lesser duration than 200ms. This
* complicates things since we would need to tack on additional
* offchannel requests to meet the 200ms requirement. This could be done
* but for now use max_roc or 200ms, whichever is less.
*/
dpp->dwell = (dpp->max_roc < 200) ? dpp->max_roc : 200;
/* "DPP R2 devices are expected to use PKEXv1 by default" */
dpp->pkex_version = 1;
if (!l_ecdh_generate_key_pair(dpp->curve, &dpp->pkex_private,
&dpp->pkex_public))
goto failed;
/*
* "If Qi is the point-at-infinity, the code shall be deleted and the
* user should be notified to provision a new code"
*/
qi = dpp_derive_qi(dpp->curve, dpp->pkex_key, dpp->pkex_id,
netdev_get_address(dpp->netdev));
if (!qi || l_ecc_point_is_infinity(qi)) {
l_debug("Cannot derive Qi, provision a new code");
goto failed;
}
dpp->pkex_m = l_ecc_point_new(dpp->curve);
if (!l_ecc_point_add(dpp->pkex_m, dpp->pkex_public, qi))
goto failed;
dpp_property_changed_notify(dpp);
/*
@ -4438,6 +4409,40 @@ static bool dpp_parse_pkex_args(struct l_dbus_message *message,
return true;
}
static bool dpp_pkex_derive_keys(struct dpp_sm *dpp)
{
_auto_(l_ecc_point_free) struct l_ecc_point *qi = NULL;
/*
* In theory a driver could support a lesser duration than 200ms. This
* complicates things since we would need to tack on additional
* offchannel requests to meet the 200ms requirement. This could be done
* but for now use max_roc or 200ms, whichever is less.
*/
dpp->dwell = (dpp->max_roc < 200) ? dpp->max_roc : 200;
/* "DPP R2 devices are expected to use PKEXv1 by default" */
dpp->pkex_version = 1;
if (!l_ecdh_generate_key_pair(dpp->curve, &dpp->pkex_private,
&dpp->pkex_public))
return false;
/*
* "If Qi is the point-at-infinity, the code shall be deleted and the
* user should be notified to provision a new code"
*/
qi = dpp_derive_qi(dpp->curve, dpp->pkex_key, dpp->pkex_id,
netdev_get_address(dpp->netdev));
if (!qi || l_ecc_point_is_infinity(qi)) {
l_debug("Cannot derive Qi, provision a new code");
return false;
}
dpp->pkex_m = l_ecc_point_new(dpp->curve);
return l_ecc_point_add(dpp->pkex_m, dpp->pkex_public, qi);
}
static struct l_dbus_message *dpp_dbus_pkex_start_enrollee(struct l_dbus *dbus,
struct l_dbus_message *message,
void *user_data)
@ -4472,6 +4477,11 @@ static struct l_dbus_message *dpp_dbus_pkex_start_enrollee(struct l_dbus *dbus,
return dbus_error_from_errno(ret, message);
}
if (!dpp_pkex_derive_keys(dpp)) {
dpp_reset(dpp);
return dbus_error_failed(message);
}
if (!wait_for_disconnect && !dpp_start_pkex_enrollee(dpp))
goto invalid_args;