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fix #1730

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`WHO #channel o` is supposed to return only server operators.
This is RFC1459 cruft; just return an empty list in this case.
This commit is contained in:
Shivaram Lingamneni 2021-11-14 14:03:02 -05:00
parent bd4f80586f
commit bdff4e633f
1 changed files with 12 additions and 7 deletions
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19
irc/handlers.go
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@ -3341,12 +3341,18 @@ func whoHandler(server *Server, client *Client, msg ircmsg.Message, rb *Response
fields = fields.Add(field)
}
//TODO(dan): is this used and would I put this param in the Modern doc?
// if not, can we remove it?
//var operatorOnly bool
//if len(msg.Params) > 1 && msg.Params[1] == "o" {
// operatorOnly = true
//}
// successfully parsed query, ensure we send the success response:
defer func() {
rb.Add(nil, server.name, RPL_ENDOFWHO, client.Nick(), origMask, client.t("End of WHO list"))
}()
// XXX #1730: https://datatracker.ietf.org/doc/html/rfc1459#section-4.5.1
// 'If the "o" parameter is passed only operators are returned according to
// the name mask supplied.'
// see discussion on #1730, we just return no results in this case.
if len(msg.Params) > 1 && msg.Params[1] == "o" {
return false
}
oper := client.Oper()
hasPrivs := oper.HasRoleCapab("sajoin")
@ -3400,7 +3406,6 @@ func whoHandler(server *Server, client *Client, msg ircmsg.Message, rb *Response
}
}
rb.Add(nil, server.name, RPL_ENDOFWHO, client.nick, origMask, client.t("End of WHO list"))
return false
}